查了一些资料之后，发现是因为computed没有显式声明返回类型。. Technically, TypeScript is right, id is possibly undefined: the enabled option does not perform any type narrowing. Property 'value' does not exist on type 'HTMLElement'. Typescript 시작 | Daily Log - GitHub Pages Since TFactor can be a TExpression, but TExpression can also be TFactor, this problem arises. In the world of Javascript this stuff is moving so fast it almost not worth writing a . Property does not exist on type 'AxiosResponse '._wflynn的博客-程序员秘密 Typescript types do not make sense · Issue #4176 - GitHub Because TypeScript does not know that MyFancyType DOES have the properties 'price' and 'expiration'.. vue.js - axios.get.mockResolvedValue() is marked as problem in testfile ... Axios Response does not only contain the response body, it is an object containing all the details about the request, the response, etc. Property does not exist on type 'AxiosResponse '. Type 'AxiosResponse<unknown, any>' is not assignable to type 'AxiosResponse<ContestType, any>'. var hogehoge = uiouio.hogehoge; const response = await axios.get (url) logPaginatedResponse (response) After receiving a response and storing it in the response variable above, I am passing the variable to the logPaginatedResponse function to log the response to the console. // Equivalent to `const data = await axios . Go to Dashboard > Application Settings and scroll to the Application Tokens section. Kind regards! We can force Typescript to treat axios.get as an Object literal by wrapping it as Object(axios.get), but: What is the idiomatic way to mock functions while maintaining type safety? 꼭 T 일 필요는 없고, cool, test 와 같이 다른 문자열을 쓸 수 있다. Also, there are ways to bypass the enabled option, for example by calling the refetch method returned from useQuery.In that case, the id might really be undefined.. I've found the best way to go here, if you don't like the non-null assertion operator, is to accept that id can be .